Guidelines for Better Coding Style

Tip - 

1. Rules of binding references to rvalues.

2. The notion of comma-separated expressions .

Details -

1. Binding a Reference to an Rvalue

Rvalues and lvalues are a fundamental concept of C++ programming. In essence, an rvalue is an expression that cannot appear on the left-hand side of an assignment expression. By contrast, an lvalue refers to an object (in its wider sense), or a chunk of memory, to which you can write a value. References can be bound to both rvalues and lvalues. However, due to the language's restrictions regarding rvalues, you have to be aware of the restrictions on binding references to rvalues, too.

Binding a reference to an rvalue is allowed as long as the reference is bound to a const type. The rationale behind this rule is straightforward: you can't change an rvalue, and only a reference to const ensures that the program doesn't modify an rvalue through its reference. In the following example, the function f() takes a reference to const int:

void f(const int & i);

int main()

{

 f(2); /* OK */

}

The program passes the rvalue 2 as an argument to f(). At runtime, C++ creates a temporary object of type int with the value 2 and binds it to the reference i. The temporary and its reference exist from the moment f() is invoked until it returns; they are destroyed immediately afterwards. Note that had we declared the reference i without the const qualifier, the function f() could have modified its argument, thereby causing undefined behavior. For this reason, you may only bind references to const objects.

2. Comma-Separated Expressions
Comma-separated expressions were inherited from C. It's likely that you use such expressions in for- and while-loops rather often. Yet, the language rules in this regard are far from being intuitive. First, let's see what a comma separated expression is.

An expression may consist of one or more sub-expressions separated by commas. For example:

if(++x, --y, cin.good()) /*three expressions*/

The if condition contains three expressions separated by commas. C++ ensures that each of the expressions is evaluated and its side effects take place. However, the value of an entire comma-separated expression is only the result of the rightmost expression. Therefore, the if condition above evaluates as true only if cin.good() returns true. Here's another example of a comma expression:

int j=10;

int i=0;

while( ++i, --j)

{

 /*..repeat as long as j is not 0*/

}

Reference         -

http://www.devx.com/cplus/Article/16328/0/page/2

Posted By :Ajay Kumar S.